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Question Number 135378 by Bird last updated on 12/Mar/21
compare without calculator  5((√(1+(√7)))−1) and 7((√(1+(√5)))−1)
comparewithoutcalculator5(1+71)and7(1+51)
Answered by mr W last updated on 12/Mar/21
5((√(1+(√7)))−1)<5((√(1+(√9)))−1)=5    7((√(1+(√5)))−1)>7((√(1+(√4)))−1)=7((√3)−1)  =7(√3)−7=7(√((147)/(49)))−7>7(√((144)/(49)))−7  =7×((12)/7)−7=12−7=5    since 7((√(1+(√5)))−1)>5 and  5((√(1+(√7)))−1)<5,  ⇒7((√(1+(√5)))−1)>5((√(1+(√7)))−1)
5(1+71)<5(1+91)=57(1+51)>7(1+41)=7(31)=737=7147497>7144497=7×1277=127=5since7(1+51)>5and5(1+71)<5,7(1+51)>5(1+71)
Commented by mathmax by abdo last updated on 12/Mar/21
thankx sir mrw
thankxsirmrw

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