cos-4-x-sinx-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 11147 by suci last updated on 14/Mar/17 ∫cos4xsinxdx=….??? Answered by ajfour last updated on 14/Mar/17 =−cos5x5+C Commented by ajfour last updated on 14/Mar/17 letcosx=tsinxdx=−dt∫cos4xsinxdx=−∫t4dt=−t55+C Answered by Mechas88 last updated on 17/Mar/17 ∫cos4xsinxdx=∫12(sin(x+4x)+sin(x−4x))dx=12∫sin5xdx+1/2∫sin−3xdx=−cos5x10+12×cos3x3+Ccos3x6−cos5x10+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-3-1-2x-dx-Next Next post: x-5-x-3-1-1-3-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.