cos4xsin4x-

Question Number 7587 by ten last updated on 05/Sep/16

c o s 4 x s i n 4 x

Answered by Rasheed Soomro last updated on 05/Sep/16

c o s 4 x s i n 4 x

\cos α \sin β = (1 / 2) [\sin (α + β) - \sin (α - β)]

\cos 4 x \sin 4 x = (1 / 2) [\sin (4 x + 4 x) - \sin (4 x - 4 x)]

= (1 / 2) \sin 8 x

O r

\cos 4 x \sin 4 x = (1 / 2) (2 \cos 4 x \sin 4 x)

2 \sin θ \cos θ = \sin 2 θ

= (1 / 2) \sin 8 x