Question Number 135065 by liberty last updated on 10/Mar/21
$$\mathrm{cosec}\:^{\mathrm{2}} \mathrm{68}°\:+\mathrm{sec}\:^{\mathrm{2}} \mathrm{56}°\:−\mathrm{cot}\:^{\mathrm{2}} \mathrm{34}°\:−\mathrm{tan}\:^{\mathrm{2}} \mathrm{22}°\:=? \\ $$
Commented by som(math1967) last updated on 10/Mar/21
$$\mathrm{2} \\ $$
Commented by som(math1967) last updated on 10/Mar/21
$${cosec}^{\mathrm{2}} \mathrm{68}−{cot}^{\mathrm{2}} \left(\mathrm{90}−\mathrm{22}\right) \\ $$$$+{sec}^{\mathrm{2}} \mathrm{56}−{tan}^{\mathrm{2}} \left(\mathrm{90}−\mathrm{34}\right) \\ $$$${cosec}^{\mathrm{2}} \mathrm{68}−{cot}^{\mathrm{2}} \mathrm{68}+{sec}^{\mathrm{2}} \mathrm{56}−{tan}^{\mathrm{2}} \mathrm{56} \\ $$$$=\mathrm{1}+\mathrm{1}=\mathrm{2} \\ $$