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d-2-y-dx-2-dy-




Question Number 136892 by Rayan1997 last updated on 27/Mar/21
∫(d^2 y/dx^2 )dy
$$\int\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }{dy} \\ $$$$ \\ $$
Answered by Olaf last updated on 27/Mar/21
F(x) = ∫(d^2 y/dx^2 )dy  F(x) = ∫((d^2 y/dx^2 ))((dy/dx))dx  F(x) = ∫y′′y′dx  F(x) = (1/2)y′^2 +C
$$\mathrm{F}\left({x}\right)\:=\:\int\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }{dy} \\ $$$$\mathrm{F}\left({x}\right)\:=\:\int\left(\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\right)\left(\frac{{dy}}{{dx}}\right){dx} \\ $$$$\mathrm{F}\left({x}\right)\:=\:\int{y}''{y}'{dx} \\ $$$$\mathrm{F}\left({x}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}{y}'^{\mathrm{2}} +\mathrm{C} \\ $$

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