Question Number 68703 by Maclaurin Stickker last updated on 15/Sep/19

Commented by MJS last updated on 15/Sep/19
![(d/dx)[ln (√((x^2 −1)/(x^2 +1)))]=(1/2)×(d/dx)[ln ((x^2 −1)/(x^2 +1))]= =(1/2)×((x^2 +1)/(x^2 −1))×((2x(x^2 +1)−2x(x^2 −1))/((x^2 +1)^2 ))= =((2x)/(x^4 −1))](https://www.tinkutara.com/question/Q68748.png)
Commented by Prithwish sen last updated on 15/Sep/19

Commented by Maclaurin Stickker last updated on 15/Sep/19

Commented by Prithwish sen last updated on 15/Sep/19

Commented by mathmax by abdo last updated on 15/Sep/19
