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d-dx-log-10-x-




Question Number 70705 by sadimuhmud 136 last updated on 07/Oct/19
(d/dx)(log_(10) x)=?
ddx(log10x)=?
Answered by $@ty@m123 last updated on 07/Oct/19
(d/dx)(((log_e  x.)/(log_e  10)))=(1/(ln 10)).(d/dx)(ln x)  =(1/(ln 10)).(1/x)  =(1/(x.ln 10))
ddx(logex.loge10)=1ln10.ddx(lnx)=1ln10.1x=1x.ln10

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