Daniel-and-Bruno-are-playing-with-perfect-cube-Daniel-is-the-first-player-if-he-obtains-1-or-2-he-wins-the-game-and-the-party-stopping-or-else-Bruno-plays-and-if-he-have-3-4-6-Bruno-won-and-the-game

Question Number 141692 by ArielVyny last updated on 22/May/21

D a n i e l a n d B r u n o a r e p l a y i n g w i t h p e r f e c t c u b e

D a n i e l i s t h e f i r s t p l a y e r i f h e o b t a i n s 1 o r 2

h e w i n s t h e g a m e a n d t h e p a r t y s t o p p i n g

o r e l s e B r u n o p l a y s a n d i f h e h a v e {3.4.6} B r u n o w o n a n d t h e g a m e s t o p p i n g

D e t e r m i n e t h e p r o b a b i l i t y t h a t D a n i e l w i n a n d t h e p r o b a b i l i t y t h a t B r u n o w i n

Answered by MJS_new last updated on 22/May/21

in \frac{1}{3} of all cases Daniel wins

in \frac{2}{3} of all cases Bruno plays

in \frac{3}{6} = \frac{1}{2} of these cases Bruno wins

the rest end in a draw

\Rightarrow

Daniel wins \frac{1}{3}

Bruno wins \frac{2}{3} \times \frac{1}{2} = \frac{1}{3}

draw \frac{1}{3}

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