Question Number 67902 by ramirez105 last updated on 01/Sep/19
$${differential}\:{equation} \\ $$$${homogenous}. \\ $$$$ \\ $$$${please}\:{answer}\:{this}.{with}\:{p}.{s}. \\ $$$${xydx}+\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{2}{y}^{\mathrm{2}} \right){dy}=\mathrm{0} \\ $$$${x}=\mathrm{0} \\ $$$${y}=\mathrm{1} \\ $$