Question Number 66099 by olalekan2 last updated on 09/Aug/19
$${differentiate}\:{y}=\mathrm{10}^{\mathrm{1}−{sin}^{\mathrm{2}} \mathrm{3}{x}} \\ $$
Commented by mathmax by abdo last updated on 09/Aug/19
$${y}\left({x}\right)\:=\mathrm{10}^{\mathrm{1}−{sin}^{\mathrm{2}} \left(\mathrm{3}{x}\right)} \:\Rightarrow{y}\left({x}\right)\:={e}^{\left(\mathrm{1}−{sin}^{\mathrm{2}} \left(\mathrm{3}{x}\right)\right){ln}\left(\mathrm{10}\right)} \:\Rightarrow \\ $$$${y}^{'} \left({x}\right)\:={ln}\left(\mathrm{10}\right)\left(−\mathrm{6}{cos}\left(\mathrm{3}{x}\right)\:{sin}\left(\mathrm{3}{x}\right)\right){y}\left({x}\right)=−\mathrm{6}{ln}\left(\mathrm{10}\right){cos}\left(\mathrm{3}{x}\right){sin}\left(\mathrm{3}{x}\right){y}\left({x}\right) \\ $$