dx-pi-e-x-2-1-x-

Question Number 68094 by mhmd last updated on 04/Sep/19

\int d x / \sqrt[x]{{(π + e)}^{x^{2}}}

Answered by MJS last updated on 05/Sep/19

\int \frac{d x}{\sqrt[x]{{(π + e)}^{x^{2}}}} = \int \frac{d x}{{(π + e)}^{x}} = - \frac{1}{{(π + e)}^{x} \ln (π + e)} + C

[\int a^{x} d x = \frac{a^{x}}{\ln a}; a = {(π + e)}^{- 1}]

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