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dx-x-2-4x-1-




Question Number 143248 by cesarL last updated on 11/Jun/21
∫(dx/(x^2 −4x+1))
$$\int\frac{{dx}}{{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}} \\ $$
Commented by mohammad17 last updated on 11/Jun/21
  =∫ (dx/((x−2)^2 −3))=(1/3)∫ ((−dx)/(1−(((x−2)/( (√3))))^2 ))=(1/( (√3)))coth^(−1) (((x−2)/( (√3))))+C    ⟨mohammad aldolaimy⟩
$$ \\ $$$$=\int\:\frac{{dx}}{\left({x}−\mathrm{2}\right)^{\mathrm{2}} −\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{3}}\int\:\frac{−{dx}}{\mathrm{1}−\left(\frac{{x}−\mathrm{2}}{\:\sqrt{\mathrm{3}}}\right)^{\mathrm{2}} }=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}{coth}^{−\mathrm{1}} \left(\frac{{x}−\mathrm{2}}{\:\sqrt{\mathrm{3}}}\right)+{C} \\ $$$$ \\ $$$$\langle{mohammad}\:{aldolaimy}\rangle \\ $$
Answered by cesarL last updated on 11/Jun/21
thank u sir, you have whatsapp?
$${thank}\:{u}\:{sir},\:{you}\:{have}\:{whatsapp}? \\ $$

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