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e-1-x-x-2-dx-




Question Number 138998 by ZiYangLee last updated on 21/Apr/21
∫ ((e^(−1/x) /x^2 )) dx =?
$$\int\:\left(\frac{{e}^{−\mathrm{1}/{x}} }{{x}^{\mathrm{2}} }\right)\:{dx}\:=? \\ $$
Answered by phanphuoc last updated on 21/Apr/21
=∫e^((−1/x)) d(−1/x)=e^(−1/x) +c
$$=\int{e}^{\left(−\mathrm{1}/{x}\right)} {d}\left(−\mathrm{1}/{x}\right)={e}^{−\mathrm{1}/{x}} +{c} \\ $$

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