Question Number 132612 by aurpeyz last updated on 15/Feb/21
$$\int{e}^{{x}+{e}^{{x}} } {dx} \\ $$
Answered by Dwaipayan Shikari last updated on 15/Feb/21
$$\int{e}^{{x}} {e}^{{e}^{{x}} } {dx}\:\:\:\:\:\:\:\:\:\:\:\:\:\:{e}^{{x}} ={t} \\ $$$$=\int{e}^{{t}} {dt}={e}^{{t}} +{C}={e}^{{e}^{{x}} } +{C} \\ $$