Evaluate-1-3-x-1-x-1-2-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 11406 by tawa last updated on 24/Mar/17 Evaluate:∫13x−1(x+1)2dx Answered by sm3l2996 last updated on 24/Mar/17 x−1(x+1)2=ax+1+b(x+1)2b=−2;a=1I=∫13x−1(x+1)2dx=∫13dxx+1−2∫13dx(x+1)2=[ln∣x+1∣]13+2[1x+1]13=ln(2)−12 Commented by tawa last updated on 24/Mar/17 Godblessyousir. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: We-usually-have-to-write-the-date-in-this-form-01-01-2020-to-mean-the-1-st-january-2020-What-is-the-first-date-that-is-written-in-this-form-with-eight-different-figures-an-example-25-09-1873-Next Next post: Question-142477 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![((x−1)/((x+1)^2 ))=(a/(x+1))+(b/((x+1)^2 )) b=−2 ; a=1 I=∫_1 ^3 ((x−1)/((x+1)^2 ))dx=∫_1 ^3 (dx/(x+1))−2∫_1 ^3 (dx/((x+1)^2 )) =[ln∣x+1∣]_1 ^3 +2[(1/(x+1))]_1 ^3 =ln(2)−(1/2)](https://www.tinkutara.com/question/Q11407.png)
