Evaluate-1-cos-2-x-dx-

Question Number 12102 by Nayon last updated on 13/Apr/17

E v a l u a t e \int \frac{1}{{c o s}^{2} (x)} d x

Answered by sma3l2996 last updated on 13/Apr/17

A = \int \frac{1}{{c o s}^{2} x} d x = t a n (x) + C

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 13/Apr/17

I = \int \frac{d x}{{c o s}^{2} x} = \int (1 + {t g}^{2} x) d x

= \int d x + \int {t g}^{2} x d x = x + t g x - x + C = t g x + C