Menu Close

Evaluate-4-5-2-ln-x-dx-using-trapezoidal-rule-take-h-0-2-




Question Number 9623 by tawakalitu last updated on 21/Dec/16
Evaluate : ∫_4 ^(5.2)  ln(x) dx    using trapezoidal rule. take h = 0.2
Evaluate:45.2ln(x)dxusingtrapezoidalrule.takeh=0.2
Commented by sandy_suhendra last updated on 21/Dec/16
Answered by sandy_suhendra last updated on 21/Dec/16
∫_4 ^(  5.2)  ln x dx   ≈((Δx)/2)[f(4)+2f(4.2)+2f(4.4)+...+2f(5)+f(5.2)]  ≈((0.2)/2)[ln4+2ln4.2+...+2ln5+ln5.2]  ≈0.1 ln [4×4.2^2 ×4.4^2 ×4.6^2 ×4.8^2 ×5^2 ×5.2]  ≈0.1×18.24 (I use calculator)  ≈1.824
45.2lnxdxΔx2[f(4)+2f(4.2)+2f(4.4)++2f(5)+f(5.2)]0.22[ln4+2ln4.2++2ln5+ln5.2]0.1ln[4×4.22×4.42×4.62×4.82×52×5.2]0.1×18.24(Iusecalculator)1.824
Commented by tawakalitu last updated on 21/Dec/16
i really appreciate your effort sir. God bless  you.
ireallyappreciateyoureffortsir.Godblessyou.

Leave a Reply

Your email address will not be published. Required fields are marked *