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Question Number 74753 by necxxx last updated on 30/Nov/19
evaluate 5^(√(log 7_5 ))  − 7^(√(log 5_7 ))
evaluate5log757log57
Commented by mr W last updated on 30/Nov/19
what is log 7_5 ? the same as log_5  7 ?
whatislog75?thesameaslog57?
Commented by Kunal12588 last updated on 30/Nov/19
define log a_b
definelogab
Commented by turbo msup by abdo last updated on 30/Nov/19
perhaps  log7_5   mean log_5 (7)...
perhapslog75meanlog5(7)
Commented by necxxx last updated on 01/Dec/19
exactly, thats what i meant. i only  didnt represent it properly.
exactly,thatswhatimeant.ionlydidntrepresentitproperly.
Answered by MJS last updated on 30/Nov/19
we had this before, in correct syntax  a^(√(log_a  b )) =a^(√((ln b)/(ln a))) =       [ln (a^(√((ln b)/(ln a))) )=(√((ln b)/(ln a)))×ln a =(√(ln a ×ln b))]  =e^(√(ln a ×ln b))   ⇒ answer is 0
wehadthisbefore,incorrectsyntaxalogab=alnblna=[ln(alnblna)=lnblna×lna=lna×lnb]=elna×lnbansweris0
Commented by necxxx last updated on 01/Dec/19
thank you so much.I do understand it  now.
thankyousomuch.Idounderstanditnow.

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