evaluate-7-log64-3-log-24-8-log-2-8-log-1-4-64-1-log-4-1-64-

Question Number 143475 by Ghaniy last updated on 14/Jun/21

e v a l u a t e;

\frac{{(\sqrt{7})}^{\log 64} - {(3)}^{\log_{24} 8}}{(\log_{2} 8 - \log_{\frac{1}{4}} 64) (\frac{1}{\log_{4} (\frac{1}{64})})}

Commented by amin96 last updated on 14/Jun/21

s u p e r

Answered by Ar Brandon last updated on 15/Jun/21

ℵ = \frac{{(\sqrt{7})}^{\log_{49} 64} - {(3)}^{\log_{24} 8}}{(\log_{2} 8 - \log_{\frac{1}{4}} 64) (\frac{1}{\log_{4} (\frac{1}{64})})}

= \frac{7^{\frac{1}{2} \cdot \frac{1}{2} \log_{7} 64} - 3^{\log_{24} 8}}{(3 + 3) (- \frac{1}{3})} = - \frac{64^{\frac{1}{4}} - 3^{\log_{24} 8}}{2}

= \frac{1}{2} \cdot 3^{\log_{24} 8} - \sqrt{2} = \dots

Commented by Ghaniy last updated on 15/Jun/21

t h a n k s

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