Question Number 191 by 123456 last updated on 25/Jan/15
![evaluate ∫_C ((z^2 sin z cos z)/((z^2 +1)(z^2 −1)))dz where C={z∈C∣∣z∣=2}](https://www.tinkutara.com/question/Q191.png)
$$\mathrm{evaluate}\:\underset{\mathrm{C}} {\int}\frac{{z}^{\mathrm{2}} \mathrm{sin}\:{z}\:\mathrm{cos}\:{z}}{\left({z}^{\mathrm{2}} +\mathrm{1}\right)\left({z}^{\mathrm{2}} −\mathrm{1}\right)}{dz}\: \\ $$$$\mathrm{where}\:\mathrm{C}=\left\{{z}\in\mathbb{C}\mid\mid{z}\mid=\mathrm{2}\right\} \\ $$
Answered by nileshkulkarni last updated on 15/Dec/14
![Apply Residue theorm. Poles of the fuction are z= i. z=−i. z=1. z=−1 evaluating the fuction at these four poles and then adding it gives 0](https://www.tinkutara.com/question/Q199.png)
$$ \\ $$$$ \\ $$$${Apply}\:{Residue}\:{theorm}.\:{Poles}\:{of}\:{the} \\ $$$${fuction}\:{are}\:{z}=\:{i}.\:\:{z}=−{i}.\:\:{z}=\mathrm{1}.\:\:\:\:{z}=−\mathrm{1} \\ $$$$ \\ $$$${evaluating}\:{the}\:{fuction}\:{at}\:{these}\:{four} \\ $$$${poles}\:{and}\:{then}\:{adding}\:{it}\:{gives}\:\mathrm{0} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$