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Question Number 11 by user1 last updated on 25/Jan/15
Evaluate: determinant (((x^2 −x+1),(x−1)),(( x+1),(x+1)))
Evaluate:|x2−x+1x−1x+1x+1|
Answered by user1 last updated on 30/Oct/14
=[(x^2 −x+1)(x+1)−(x+1)(x−1)] =[(x^3 +1)−(x^2 −1)] =(x^3 −x^2 +2)
=[(x2−x+1)(x+1)−(x+1)(x−1)]=[(x3+1)−(x2−1)]=(x3−x2+2)

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