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evaluate-sin-1-x-1-x-2-dx-




Question Number 8782 by uchechukwu okorie favour last updated on 27/Oct/16
evaluate; ∫((sin^(−1) x)/( (√(1−x^2 ))))dx
evaluate;sin1x1x2dx
Answered by prakash jain last updated on 27/Oct/16
sin^(−1) x=u  (1/( (√(1−x^2 ))))dx=du  ∫((sin^(−1) x)/( (√(1−x^2 ))))dx=∫udu=(u^2 /2)+C=(((sin^(−1) x)^2 )/2)+C
sin1x=u11x2dx=dusin1x1x2dx=udu=u22+C=(sin1x)22+C

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