evaluate-sin-1-x-1-x-2-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 8782 by uchechukwu okorie favour last updated on 27/Oct/16 evaluate;∫sin−1x1−x2dx Answered by prakash jain last updated on 27/Oct/16 sin−1x=u11−x2dx=du∫sin−1x1−x2dx=∫udu=u22+C=(sin−1x)22+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Father-reduced-the-quantity-of-food-bought-for-the-family-by-25-2-When-he-found-that-the-cost-of-living-has-increased-by-15-What-is-the-fraction-increase-in-the-family-s-food-bill-now-Next Next post: Question-8785 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.