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Question Number 120 by novrya last updated on 25/Jan/15
Evaluate ∫tan θ dθ
Evaluate∫tanθdθ
Answered by ssahoo last updated on 06/Dec/14
∫tan θ dθ =∫((sin θ)/(cos θ))dθ substituting cos θ=y −sin θdθ=dy ∫((sin θ)/(cos θ))dθ=∫− (dy/y) =−ln ∣y∣+C =−ln ∣cos θ∣+C
∫tanθdθ=∫sinθcosθdθsubstitutingcosθ=y−sinθdθ=dy∫sinθcosθdθ=∫−dyy=−ln∣y∣+C=−ln∣cosθ∣+C

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