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Question Number 132682 by otchereabdullai@gmail.com last updated on 15/Feb/21
expand 1−x^8
expand1x8
Answered by MJS_new last updated on 15/Feb/21
1−x^8 =(1−x^4 )(1+x^4 )=(1−x^2 )(1+x^2 )(1+x^4 )=  =(1−x)(1+x)(1+x^2 )(1+x^4 )
1x8=(1x4)(1+x4)=(1x2)(1+x2)(1+x4)==(1x)(1+x)(1+x2)(1+x4)
Commented by otchereabdullai@gmail.com last updated on 15/Feb/21
God bless u prof mjs
Godblessuprofmjs
Answered by mathmax by abdo last updated on 16/Feb/21
1−x^8  =1−(x^4 )^2  =(1−x^4 )(1+x^4 )=(1−x^2 )(1+x^2 )(1+x^4 )  =(1−x)(1+x)(1+x^2 )((1+x^2 )^2 −2x^2 )  =(1−x)(1+x)(1+x^2 )(x^2 −(√2)x+1)(x^2  +(√2)x +1)
1x8=1(x4)2=(1x4)(1+x4)=(1x2)(1+x2)(1+x4)=(1x)(1+x)(1+x2)((1+x2)22x2)=(1x)(1+x)(1+x2)(x22x+1)(x2+2x+1)

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