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Question Number 9400 by tawakalitu last updated on 04/Dec/16
expand :  y = e^x  , about the point x = 1  using taylor′s series.
expand:y=ex,aboutthepointx=1usingtaylorsseries.
Answered by 123456 last updated on 04/Dec/16
y=(dy/dx)=... for y=e^x   taylor serie  y=Σ_(n=0) ^∞ ((f^((n)) (a))/(n!))(x−a)^n     ∣x−a∣<R  f^((n)) (a) mean n th derivate  so we get  e^x =Σ_(n=0) ^∞ ((e(x−1)^n )/(n!))
y=dydx=fory=extaylorseriey=n=0f(n)(a)n!(xa)nxa∣<Rf(n)(a)meannthderivatesowegetex=n=0e(x1)nn!

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