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express-the-folowing-in-the0-6-bar-form-of-p-q-where-p-and-q-are-integers-and-q-is-not-0-0-6-




Question Number 139 by shaleen last updated on 25/Jan/15
express the folowing in the0.6(bar)=  form of p/q ;where p and q  are integers and q is not =0  0.6^�
expressthefolowinginthe0.6(bar)=formofp/q;wherepandqareintegersandqisnot=00.6¯
Answered by vkulkarni last updated on 10/Dec/14
0.6^(−) =0.6666666....  =(6/(10))+(6/(100))+(6/(1000))+(6/(10^4 ))+....  This is an infinite G.P. with first  term, a=(6/(10)) and r=(1/(10)), hence  0.6^− =(a/(1−r))=(( (6/(10)))/(1−(1/(10))))=(6/9)=(2/3)
0.6=0.6666666.=610+6100+61000+6104+.ThisisaninfiniteG.P.withfirstterm,a=610andr=110,hence0.6=a1r=6101110=69=23