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expressf-8cos-15sin-in-the-form-rcos-where-r-gt-0-and-is-a-positive-acute-angle-hence-find-the-general-solution-of-the-equation-80cos-150sin-13-the-maximum-and-minimum-value-




Question Number 73544 by Rio Michael last updated on 13/Nov/19
expressf(θ)= 8cosθ −15sinθ in the form   rcos(θ + α), where r>0 and α is a positive acute angle  hence  find the general solution of the equation    80cos θ −150sinθ = 13  the maximum and minimum value of  (5/(f(θ) + 3))
expressf(θ)=8cosθ15sinθintheformrcos(θ+α),wherer>0andαisapositiveacuteanglehencefindthegeneralsolutionoftheequation80cosθ150sinθ=13themaximumandminimumvalueof5f(θ)+3
Answered by mind is power last updated on 13/Nov/19
8cos(θ)−15sin(θ)=17{(8/(17))cos(θ)−((15)/(17))sin(θ)}  =17cos(θ+arcos((8/(17))))  α=arcos((8/(17)))  80cos(θ)−150sin(θ)=170cos(θ+α)=13  cos(θ+α)=((13)/(170))  θ+α=+_− arcos(((13)/(170)))+2kπ  min and max  didnt exist  since f(θ)=−3 hase solution
8cos(θ)15sin(θ)=17{817cos(θ)1517sin(θ)}=17cos(θ+arcos(817))α=arcos(817)80cos(θ)150sin(θ)=170cos(θ+α)=13cos(θ+α)=13170θ+α=+arcos(13170)+2kπminandmaxdidntexistsincef(θ)=3hasesolution
Commented by Rio Michael last updated on 13/Nov/19
wonderful sir
wonderfulsir

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