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f-0-R-a-N-R-a-n-1-f-a-n-a-n-f-x-f-y-x-y-0-does-a-n-a-m-n-m-0-




Question Number 1963 by 123456 last updated on 26/Oct/15
f:[0,+∞)→R,a:N→R  a_(n+1) =f(a_n )−a_n   f(x)≥f(y),∀x≥y≥0  does  a_n ≥a_m ,∀n≥m≥0?
f:[0,+)R,a:NRan+1=f(an)anf(x)f(y),xy0doesanam,nm0?
Answered by prakash jain last updated on 26/Oct/15
Counter example  a_0 =1  f(1)=0⇒f(a_0 )=0  a_1 =0−1=−1  a_1 <a_0
Counterexamplea0=1f(1)=0f(a0)=0a1=01=1a1<a0
Commented by Rasheed Soomro last updated on 27/Oct/15
a_0 =1 Assumed?  f(1)=0 How? Is it also assumption?  Question for sake of understanding/Knowledge.  Not objection.
a0=1Assumed?f(1)=0How?Isitalsoassumption?Questionforsakeofunderstanding/Knowledge.Notobjection.
Commented by prakash jain last updated on 27/Oct/15
Values assumed which satisfy the given  conditions in question to create a counter  example.  We can also use a_(1 )  and a_2  and use differnt  values to create a counter example as long as  f(a_1 )−a_1 <a_1   f(a_1 )<2a_1
Valuesassumedwhichsatisfythegivenconditionsinquestiontocreateacounterexample.Wecanalsousea1anda2andusedifferntvaluestocreateacounterexampleaslongasf(a1)a1<a1f(a1)<2a1
Commented by Rasheed Soomro last updated on 27/Oct/15
THANK^S  !
THANKS!

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