Question Number 7686 by Alimudin last updated on 09/Sep/16
$${f}\:×=\left(\mathrm{81}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{2}\left(\mathrm{9}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{4} \\ $$$$\left(\mathrm{2}+\frac{\mathrm{1}}{×}\right)^{\mathrm{3}} =… \\ $$$$ \\ $$
Commented by Rasheed Soomro last updated on 09/Sep/16
$${Do}\:{you}\:{mean} \\ $$$${x}=\left(\mathrm{81}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{2}\left(\mathrm{9}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{4} \\ $$$$\left(\mathrm{2}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{3}} =…\:\:\:\:\:\:\:? \\ $$