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f-R-R-f-xy-f-x-y-f-x-f-y-f-x-f-y-f-1-f-0-f-1-




Question Number 1130 by 123456 last updated on 22/Jun/15
f:R→R  f(xy)+f(x+y)=f(x)f(y)+f(x)+f(y)  f(−1)=?  f(0)=?  f(+1)=?
f:RRf(xy)+f(x+y)=f(x)f(y)+f(x)+f(y)f(1)=?f(0)=?f(+1)=?
Answered by prakash jain last updated on 23/Jun/15
f(x)=x  f(x+y)+f(xy)=x+y+xy=f(x)+f(y)+f(x)f(y)  f(0)=0  f(1)=1  f(−1)=−1
f(x)=xf(x+y)+f(xy)=x+y+xy=f(x)+f(y)+f(x)f(y)f(0)=0f(1)=1f(1)=1
Commented by Rasheed Soomro last updated on 15/Jul/15
You have proved yourself as an intelligent mathematition!
Youhaveprovedyourselfasanintelligentmathematition!

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