Question Number 134237 by mathlove last updated on 01/Mar/21
$${f}\left({x}\right)=\frac{\mathrm{2}{x}^{\mathrm{100}!} }{\left(\mathrm{100}!\right)!}+{x}^{\mathrm{100}} +\mathrm{1} \\ $$$${faind}\:\:\:\:\:\frac{{d}^{\mathrm{100}!} {f}\left({x}\right)}{{dx}^{\mathrm{100}!} }=? \\ $$
Answered by malwan last updated on 01/Mar/21
$$\frac{{d}^{\mathrm{100}!} {f}\left({x}\right)}{{dx}^{\mathrm{100}!} }\:=\:\frac{\mathrm{2}×\left(\mathrm{100}!\right)!}{\left(\mathrm{100}!\right)!}\:+\:\mathrm{0}\:+\:\mathrm{0}=\:\mathrm{2} \\ $$