Question Number 135393 by Eric002 last updated on 12/Mar/21
$${f}\:'\left({x}\right)=\frac{\left({x}−\mathrm{3}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} −\mathrm{4}\right)}{\mathrm{16}} \\ $$$${g}\left({x}\right)={f}\left({x}^{\mathrm{2}} −\mathrm{1}\right) \\ $$$${find}\:{g}'\left(\mathrm{2}\right) \\ $$
Answered by MJS_new last updated on 12/Mar/21
$${g}'\left({x}\right)=\mathrm{2}{xf}'\left({x}^{\mathrm{2}} −\mathrm{1}\right)\:\Rightarrow\:{g}'\left(\mathrm{2}\right)=\mathrm{0} \\ $$