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factorise-3k-2-2kh-8h-2-




Question Number 140828 by jlewis last updated on 13/May/21
factorise 3k^2  +2kh−8h^2
$$\mathrm{factorise}\:\mathrm{3k}^{\mathrm{2}} \:+\mathrm{2kh}−\mathrm{8h}^{\mathrm{2}} \\ $$
Answered by liberty last updated on 13/May/21
(3k  −4h  )(k+2h)
$$\left(\mathrm{3k}\:\:−\mathrm{4h}\:\:\right)\left(\mathrm{k}+\mathrm{2h}\right) \\ $$
Commented by jlewis last updated on 13/May/21
which method have u used to arrive at this
$${which}\:{method}\:{have}\:{u}\:{used}\:{to}\:{arrive}\:{at}\:{this} \\ $$
Answered by Rasheed.Sindhi last updated on 13/May/21
   3k^2  +2kh−8h^2   By breaking middle term    =3k^2 −4kh+6kh−8h^2    =k(3k−4h)+2h(3k−4h)  =(3k−4h)(k+2h)
$$\:\:\:\mathrm{3k}^{\mathrm{2}} \:+\mathrm{2kh}−\mathrm{8h}^{\mathrm{2}} \\ $$$${By}\:{breaking}\:{middle}\:{term} \\ $$$$\:\:=\mathrm{3}{k}^{\mathrm{2}} −\mathrm{4}{kh}+\mathrm{6}{kh}−\mathrm{8}{h}^{\mathrm{2}} \\ $$$$\:={k}\left(\mathrm{3}{k}−\mathrm{4}{h}\right)+\mathrm{2}{h}\left(\mathrm{3}{k}−\mathrm{4}{h}\right) \\ $$$$=\left(\mathrm{3}{k}−\mathrm{4}{h}\right)\left({k}+\mathrm{2}{h}\right) \\ $$
Commented by jlewis last updated on 13/May/21
thanks i get it now
$${thanks}\:{i}\:{get}\:{it}\:{now} \\ $$

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