Question Number 140829 by jlewis last updated on 13/May/21
$${factorise}\:\mathrm{5}{x}^{\mathrm{2}{m}} \mathrm{8}{x}^{{m}} +\mathrm{8} \\ $$
Answered by Rasheed.Sindhi last updated on 13/May/21
$$\:\mathrm{5}{x}^{\mathrm{2}{m}} \mathrm{8}{x}^{{m}} +\mathrm{8} \\ $$$$=\mathrm{8}\left(\mathrm{5}{x}^{\mathrm{3}{m}} +\mathrm{1}\right) \\ $$
Commented by MJS_new last updated on 13/May/21
$$=\mathrm{8}\left(\mathrm{5}^{\mathrm{1}/\mathrm{3}} {x}^{{m}} +\mathrm{1}\right)\left(\mathrm{5}^{\mathrm{2}/\mathrm{3}} {x}^{\mathrm{2}{m}} −\mathrm{5}^{\mathrm{1}/\mathrm{3}} {x}^{{m}} +\mathrm{1}\right) \\ $$