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Question Number 6946 by 314159 last updated on 03/Aug/16
Find all continuous functions f(x) such   that f(2x+1)=f(x) for all real x.
Findallcontinuousfunctionsf(x)suchthatf(2x+1)=f(x)forallrealx.
Commented by Yozzii last updated on 04/Aug/16
f(1)=f(0)  f′(x)=2f′(2x+1)  f(x)=c∈R⇒ f(2x+1)=c=f(x) ∀x∈R
f(1)=f(0)f(x)=2f(2x+1)f(x)=cRf(2x+1)=c=f(x)xR
Commented by Rasheed Soomro last updated on 04/Aug/16
Same answer as above but with different process   Suppose that f(x) is a linear polynomial ax+b        f(x)=ax+b        f(2x+1)=a(2x+1)+b=2ax+a+b  As    f(2x+1)=f(x)  So    2ax+a+b=ax+b  Comparing coefficients:         a=2a  ∧  a+b=b          a=0, b=b  Hence f(x)=b  Same result if f(x) be supposed? ax^2 +bx+c
SameanswerasabovebutwithdifferentprocessSupposethatf(x)isalinearpolynomialax+bf(x)=ax+bf(2x+1)=a(2x+1)+b=2ax+a+bAsf(2x+1)=f(x)So2ax+a+b=ax+bComparingcoefficients:a=2aa+b=ba=0,b=bHencef(x)=bSameresultiff(x)besupposed?ax2+bx+c

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