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Question Number 4102 by prakash jain last updated on 28/Dec/15
Find all function f:R→R  such that  f(x+1)=xf(x)  f (0)=1   f(x)≠Γ(x)
Findallfunctionf:RRsuchthatf(x+1)=xf(x)f(0)=1f(x)Γ(x)
Commented by prakash jain last updated on 28/Dec/15
Γ(x) is gamma function.
Γ(x)isgammafunction.
Commented by 123456 last updated on 28/Dec/15
i think that if function need to be continuous  then Γ is the only function
ithinkthatiffunctionneedtobecontinuousthenΓistheonlyfunction
Commented by Filup last updated on 29/Dec/15
x=0  f(0+1)=0f(0)  ∴f(1)=0  Γ(1)=1  ∴f(x)≠Γ(x)???
x=0f(0+1)=0f(0)f(1)=0Γ(1)=1f(x)Γ(x)???
Commented by 123456 last updated on 29/Dec/15
f(1)=1 for gamma function
f(1)=1forgammafunction
Commented by Filup last updated on 29/Dec/15
but if f(x)=Γ(x)  x=1  f(1)=0  Γ(1)=1  ∴f(x)≠Γ(x)  I am confused
butiff(x)=Γ(x)x=1f(1)=0Γ(1)=1f(x)Γ(x)Iamconfused
Commented by prakash jain last updated on 29/Dec/15
Find f meeting th conditions given above.  Functions other than Γ function.
Findfmeetingthconditionsgivenabove.FunctionsotherthanΓfunction.

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