Menu Close

Find-all-n-for-which-n-2-2n-4-is-divisible-by-7-




Question Number 133320 by bramlexs22 last updated on 21/Feb/21
Find all n for which n^2 +2n+4   is divisible by 7
Findallnforwhichn2+2n+4isdivisibleby7
Answered by EDWIN88 last updated on 21/Feb/21
let n = 7k+r then n^2 +2n+4 = (7k+r)^2 +2(7k+r)+4  = r^2 +2r+4 (mod 7)  cheking for r = 0,1,2,3,4,5,6   we see that r = 1 or r = 4  Hence n is of the form 7k+1 or 7k+4   i.e n ≡ 1 or 4 (mod 7 )  test n=8 ⇒n^2 +2n+4 = 64+16+4=84 is divisible by 7  test n=11⇒n^2 +2n+4=121+22+4=147 is divisible by 7
letn=7k+rthenn2+2n+4=(7k+r)2+2(7k+r)+4=r2+2r+4(mod7)chekingforr=0,1,2,3,4,5,6weseethatr=1orr=4Hencenisoftheform7k+1or7k+4i.en1or4(mod7)testn=8n2+2n+4=64+16+4=84isdivisibleby7testn=11n2+2n+4=121+22+4=147isdivisibleby7

Leave a Reply

Your email address will not be published. Required fields are marked *