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Find-all-values-for-x-x-2-7x-11-x-2-13x-42-1-Easy-




Question Number 68935 by Maclaurin Stickker last updated on 17/Sep/19
Find all values for x:  (x^2 −7x+11)^(x^2 −13x+42) =1  (Easy)
Findallvaluesforx:(x27x+11)x213x+42=1(Easy)
Answered by $@ty@m123 last updated on 17/Sep/19
x=7,6  x=2,5  (Calculated in mind.)
x=7,6x=2,5(Calculatedinmind.)
Answered by Rasheed.Sindhi last updated on 17/Sep/19
Either base=1 Or exponent=0  (x^2 −7x+11)^(x^2 −13x+42) =1  x^2 −7x+11=1 ∣  x^2 −13x+42=0  x^2 −7x+10=0 ∣ (x−6)(x−7)=0  (x−2)(x−5)=0 ∣ x=6,7  x=2,5
Eitherbase=1Orexponent=0(x27x+11)x213x+42=1x27x+11=1x213x+42=0x27x+10=0(x6)(x7)=0(x2)(x5)=0x=6,7x=2,5

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