Find-an-equation-of-the-tangent-line-to-the-curve-y-tan-2-x-at-the-point-pi-3-3-

Question Number 7900 by tawakalitu last updated on 23/Sep/16

F i n d a n e q u a t i o n o f t h e t a n g e n t l i n e t o t h e c u r v e

y = {t a n}^{2} x a t t h e p o i n t (\frac{π}{3}, 3)

Commented by sou1618 last updated on 24/Sep/16

l : t a n g e n t l i n e

3 = {t a n}^{2} (\frac{π}{3})

s o p o i n t (π / 3, 3) i s o n l

y^{'} = 2 t a n (x) \cdot {(t a n x)}^{'}

y^{'} = 2 t a n (x) \cdot \frac{1}{{c o s}^{2} x}

l : y - 3 = 2 t a n (π / 3) \cdot \frac{1}{{c o s}^{2} (π / 3)} (x - π / 3)

l : y = 2 \sqrt{3} \cdot 4 (x - π / 3) + 3

l : y = 8 \sqrt{3} x + 3 - \frac{8 π \sqrt{3}}{3}

l : y = 8 \sqrt{3} x + 3 - \frac{8 π}{\sqrt{3}} .

Commented by tawakalitu last updated on 24/Sep/16

T h a n k y o u s o m u c h .

Answered by prakash jain last updated on 02/Oct/16

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