find-complex-number-such-that-n-m-u-v-n-m-u-v-Z-Q1498- Tinku Tara June 3, 2023 Others 0 Comments FacebookTweetPin Question Number 1559 by 123456 last updated on 19/Aug/15 findcomplexnumberα,βsuchthatαn=βmβu=αvn,m,u,v∈Z\boldsymbolQ1498 Answered by Rasheed Soomro last updated on 19/Aug/15 Letgcd(m,u)=k⇒lcm(m,u)=muk(αn)uk=(βm)uk⇒αnuk=βmuk……..(\boldsymbolI)(βu)mk=(αv)mk⇒βmuk=αmvk………(\boldsymbolII)[Inordertoacheivethecommonexponent(leastalso)ofβ]From(\boldsymbolI)and(\boldsymbolII)αnuk=αmvk⇒nu=mv[Thisconditionisregardlessofvalueofαandβ]αnuk−αmvk=0αmvk(αnuk−mvk−1)=0⇒αmvk=0∨αnuk−mvk−1=0α=0∨αnuk−mvk=1[Youmayequallyproceedasαnuk(1−αmvk−nuk)=0⇒αnuk=0∨1−αmvk−nuk=0⇒α=0∨αmvk−nuk=1⇒αnuk−mvk=(1)−1=1sameasabove.]Soα=nu−mvk1I−Eαis(nu−mvgcd(m,u))\boldsymbolthrootofunity.Similarprocessshowsthatβ=0∨βis(nu−mvgcd(n,v))\boldsymbolthrootofunity.Solutionforα{0}∪{1,ω,ω2,……ω(nu−mvgcd(m,u)−1)};ωis(nu−mvgcd(m,u))\boldsymbolthrootofunity.Solutionforβ{0}∪{1,μ,μ2,….μ(nu−mvgcd(n,v)−1)};μis(nu−mvgcd(n,v))\boldsymbolthrootofunity.Let(α,β)=(ωp,μq)suchthatαn=βm∧βu=αv(ωp)n=(μq)m∧(μq)u=(ωp)vωnp=μmq∧μuq=ωvpOnsimplicationwegetmv=nu,Whichisfreeofpandqandthatmeanspandqmaybeanyintegers.HenceifAα={1,ω,ω2,……ω(nu−mvgcd(m,u)−1)}andAβ={1,μ,μ2,….μ(nu−mvgcd(n,v)−1)},thesolutionforpair(α,β)iswholeAα×Aβ Answered by Rasheed Soomro last updated on 19/Aug/15 αandβmaybeanycomplexnumbersformv=nu Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-such-that-2-3-4-5-6-Next Next post: find-all-value-of-z-its-saytisfies-1-4z-z-3-1-4z-n-0-z-n-4-n-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.