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Question Number 11552 by Nayon last updated on 28/Mar/17
find (d/dx)(y) where  y= ^(√x) (√(√x))
findddx(y)wherey=xx
Answered by ajfour last updated on 28/Mar/17
y = ((√x))^(1/( (√x)))   ln y =((ln (√x))/( (√x)))  (1/y)(dy/dx) = (((((1/( (√x)))) ((1/(2(√x))))(√x) −((ln (√x))/(2(√x))))/x))  (dy/dx) = y(((1−ln (√x))/(2x(√x))))  (dy/dx) = ((((√x) )^(1/( (√x)))   (1−ln (√x) ))/(2x(√x))) .
y=(x)1xlny=lnxx1ydydx=((1x)(12x)xlnx2xx)dydx=y(1lnx2xx)dydx=(x)1x(1lnx)2xx.

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