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find-dx-1-x-6-




Question Number 70686 by mathmax by abdo last updated on 06/Oct/19
find ∫ (dx/(1+x^6 ))
finddx1+x6
Answered by kaivan.ahmadi last updated on 06/Oct/19
Answered by MJS last updated on 07/Oct/19
∫(dx/(x^6 +1))=  =(1/3)∫(dx/(x^2 +1))+(1/6)∫(((√3)x+2)/(x^2 +(√3)x+1))dx−(1/6)∫(((√3)x−2)/(x^2 −(√3)x+1))dx=  =(1/3)arctan x +       +((√3)/(12))ln (x^2 +(√3)x+1) +(1/6)arctan (2x+(√3)) −       −((√3)/(12))ln (x^2 −(√3)x+1) +(1/6)arctan (2x−(√3)) +C
dxx6+1==13dxx2+1+163x+2x2+3x+1dx163x2x23x+1dx==13arctanx++312ln(x2+3x+1)+16arctan(2x+3)312ln(x23x+1)+16arctan(2x3)+C

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