find-lim-x-0-1-cos-x-cos-2-2x-cos-3-3x-cos-n-nx-x-2- Tinku Tara June 3, 2023 Limits 0 Comments FacebookTweetPin Question Number 133830 by metamorfose last updated on 24/Feb/21 findlimx→01−cos(x)cos2(2x)cos3(3x)…cosn(nx)x2=…? Answered by EDWIN88 last updated on 24/Feb/21 limx→01−(1−12x2)(1−82x2)(1−272x2)…(1−n32x2)x2=limx→01−(1−12x2(13+23+33+…+n3))x2=12(13+23+33+…+n3)=12[n(n+1)2]2 Answered by Dwaipayan Shikari last updated on 24/Feb/21 limx→01−cos(x)cos2(2x)cos3(3x)…cosn(nx)x2=y∑nn=1nlog(cos(nx))=log(1−x2y)limx→0log(1+x)=x∑nn=1nlog(1−n2x22)=log(1−x2y)limx→0cosx=1−x22−∑nn=1n3x22=−x2y⇒12∑nn=1n3=yy=n2(n+1)28 Answered by bramlexs22 last updated on 24/Feb/21 limx→01−cosxcos22xx2=limx→01−cosx(1−2sin2x)2x2=limx→01−(1−12x2)(1−4x2)x2=limx→01−(1−92x2+12x4)x2=92 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-133825Next Next post: Question-68294 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.