find-lim-x-x-x-2-1-

Question Number 73017 by Rio Michael last updated on 05/Nov/19

f i n d

\lim_{x \to + \infty} x \sqrt{x^{2} + 1}

Commented by mathmax by abdo last updated on 05/Nov/19

= {l i m}_{x \to + \infty} x \sqrt{x^{2} (1 + \frac{1}{x^{2}}}) = {l i m}_{x \to + \infty} x^{2} \sqrt{1 + \frac{1}{x^{2}}} = {l i m}_{x \to + \infty} x^{2} = + \infty