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Question Number 136437 by liberty last updated on 22/Mar/21
Find max and min value of   y = sin^2 x+ cos^4 x
Findmaxandminvalueofy=sin2x+cos4x
Answered by rs4089 last updated on 22/Mar/21
y=1−cos^2 x+cos^4 x  y=(3/4)+(cos^2 x−(1/2))^2   y_(min.) =(3/4)+0=(3/4)  y_(max.) =(3/4)+(1−(1/2))^2 =1
y=1cos2x+cos4xy=34+(cos2x12)2ymin.=34+0=34ymax.=34+(112)2=1

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