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Question Number 133782 by bramlexs22 last updated on 24/Feb/21
Find maximum and minimum   value of function y=cos^2 x +cos x +3   on interval 0≤x≤(π/2)
Findmaximumandminimumvalueoffunctiony=cos2x+cosx+3oninterval0xπ2
Answered by bobhans last updated on 24/Feb/21
 y=(cos x+(1/2))^2 +((11)/4)  we know 0≤cos x≤1 on interval 0≤x≤(π/2)  so (1/2)≤cos x+(1/2)≤(3/2) and    (1/4)≤(cos x+(1/2))^2 ≤(9/4) ; thus   (1/4)+((11)/4)≤(cos x+(1/2))^2 +((11)/4)≤(9/4)+((11)/4)  ⇔ 3 ≤ y ≤ 5 ⇒ { ((max value = 5)),((min value = 3)) :}
y=(cosx+12)2+114weknow0cosx1oninterval0xπ2so12cosx+1232and14(cosx+12)294;thus14+114(cosx+12)2+11494+1143y5{maxvalue=5minvalue=3
Commented by bramlexs22 last updated on 24/Feb/21

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