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Find-minimum-value-of-function-f-x-4x-2-8x-13-6-1-x-




Question Number 135211 by benjo_mathlover last updated on 11/Mar/21
Find minimum value of function  f(x) = ((4x^2 +8x+13)/(6(1+x)))
Findminimumvalueoffunctionf(x)=4x2+8x+136(1+x)
Commented by mr W last updated on 11/Mar/21
lim_(x→−1^− ) f(x)=−∞  lim_(x→−1^+ ) f(x)=+∞  ⇒there is no minimum and no  maxinum for f(x)!
limx1f(x)=limx1+f(x)=+thereisnominimumandnomaxinumforf(x)!
Commented by benjo_mathlover last updated on 11/Mar/21
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