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find-n-1-cos-nx-n-2-




Question Number 67384 by mathmax by abdo last updated on 26/Aug/19
find Σ_(n=1) ^∞  ((cos(nx))/n^2 )
findn=1cos(nx)n2
Commented by mathmax by abdo last updated on 27/Aug/19
we have proved that  Σ_(n=1) ^∞  ((sin(nx))/n) =((π−x)/2) ⇒  Σ_(n=1) ^∞  (1/n)∫  sin(nx)dx =(1/2)∫(π−x)dx +c ⇒  −Σ_(n=1) ^∞  (1/n^2 )cos(nx) =(1/2){πx−(x^2 /2)} +c =(π/2)x−(x^2 /4) +c ⇒  Σ_(n=1) ^∞  ((cos(nx))/n^2 ) =−(π/2)x +(x^2 /4) −c  x=0 ⇒Σ_(n=1) ^∞  (1/n^2 ) =−c ⇒c =−(π^2 /6) ⇒Σ_(n=1) ^∞  ((cos(nx))/n^2 ) =(x^2 /4)−((πx)/2) +(π^2 /6)
wehaveprovedthatn=1sin(nx)n=πx2n=11nsin(nx)dx=12(πx)dx+cn=11n2cos(nx)=12{πxx22}+c=π2xx24+cn=1cos(nx)n2=π2x+x24cx=0n=11n2=cc=π26n=1cos(nx)n2=x24πx2+π26

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