find-pi-6-pi-6-1-tanx-1-sin-2x-dx-

Question Number 66335 by mathmax by abdo last updated on 12/Aug/19

f i n d \int_{- \frac{π}{6}}^{\frac{π}{6}} \frac{1 + t a n x}{1 + s i n (2 x)} d x

Commented by Prithwish sen last updated on 13/Aug/19

\int_{- \frac{π}{6}}^{\frac{π}{6}} \frac{\sec^{2} x}{1 + tanx} dx = {[\ln (1 + tanx)]}_{\frac{- π}{6}}^{\frac{π}{6}} = \ln \frac{\sqrt{3} + 1}{\sqrt{3} - 1}