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Question Number 7321 by rohit meena last updated on 23/Aug/16
find sets A={x∣y=x^2 ,xεz}
$${find}\:{sets}\:{A}=\left\{{x}\mid{y}=\boldsymbol{{x}}^{\mathrm{2}} ,{x}\epsilon{z}\right\} \\ $$
Commented by rohit meena last updated on 24/Aug/16
answet plzzzz
$${answet}\:{plzzzz} \\ $$
Commented by Rasheed Soomro last updated on 24/Aug/16
Do you mean A={y∣y=x^2 ,xεz}?
$${Do}\:{you}\:{mean}\:{A}=\left\{\boldsymbol{{y}}\mid{y}=\boldsymbol{{x}}^{\mathrm{2}} ,{x}\epsilon{z}\right\}? \\ $$
Answered by Rasheed Soomro last updated on 25/Aug/16
find sets A={x∣y=x^2 ,xεz}  −−−−−−−−−−−−−−−  If the question is meant ′A={y∣y=x^2 ,xεz}′  then          A={0,1,4,9,16,25,...}
$${find}\:{sets}\:{A}=\left\{{x}\mid{y}=\boldsymbol{{x}}^{\mathrm{2}} ,{x}\epsilon{z}\right\} \\ $$$$−−−−−−−−−−−−−−− \\ $$$${If}\:{the}\:{question}\:{is}\:{meant}\:'{A}=\left\{{y}\mid{y}=\boldsymbol{{x}}^{\mathrm{2}} ,{x}\epsilon{z}\right\}' \\ $$$${then}\: \\ $$$$\:\:\:\:\:\:\:{A}=\left\{\mathrm{0},\mathrm{1},\mathrm{4},\mathrm{9},\mathrm{16},\mathrm{25},…\right\} \\ $$

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